JEE MAIN - Physics (2019 - 10th April Morning Slot - No. 19)
Figure shows charge (q) versus voltage (V)
graph for series and parallel combination of two
given capacitors. The capacitances are :
_10th_April_Morning_Slot_en_19_1.png)
40 $$\mu $$F and 10 $$\mu $$F
60 $$\mu $$F and 40 $$\mu $$F
20 $$\mu $$F and 30 $$\mu $$F
50 $$\mu $$F and 30 $$\mu $$F
Explanation
As q = CV
Hence slope of graph will give capacitance. Slope will be more in parallel combination. Hence capacitance in parallel should be 50 $$\mu $$F and in series combination must be 8 $$\mu $$F. Only in option 40 $$\mu $$f and 10 $$\mu $$F.
Cparallel = 40 + 10 = 50 $$\mu $$F
Cseries = $${{40 \times 10} \over {40 + 10}} = 8\mu F$$
Hence slope of graph will give capacitance. Slope will be more in parallel combination. Hence capacitance in parallel should be 50 $$\mu $$F and in series combination must be 8 $$\mu $$F. Only in option 40 $$\mu $$f and 10 $$\mu $$F.
Cparallel = 40 + 10 = 50 $$\mu $$F
Cseries = $${{40 \times 10} \over {40 + 10}} = 8\mu F$$
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