JEE MAIN - Physics (2019 - 10th April Evening Slot - No. 26)
A cubical block of side 0.5 m floats on water with 30% of its volume under water. What is the maximum
weight that can be put on the block without fully submerging it under water? [Take, density of water = 103
kg/m3]
30.1 kg
87.5 kg
65.4 kg
46.3 kg
Explanation
Given $${\left( {50} \right)^3} \times {{30} \over {100}} \times \left( 1 \right) \times g = {M_{cube}}g$$ ...(i)
Let m mass should be placed
Hence (50)3$$ \times $$ (1) $$ \times $$ g = (Mcube + m)g …(ii)
equation (ii) – equation (i)
$$ \Rightarrow $$ mg = (50)3 × g(1 – 0.3) = 125 × 0.7 × 103 g
$$ \Rightarrow $$ m = 87.5 kg
Let m mass should be placed
Hence (50)3$$ \times $$ (1) $$ \times $$ g = (Mcube + m)g …(ii)
equation (ii) – equation (i)
$$ \Rightarrow $$ mg = (50)3 × g(1 – 0.3) = 125 × 0.7 × 103 g
$$ \Rightarrow $$ m = 87.5 kg
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