JEE MAIN - Physics (2019 - 10th April Evening Slot - No. 23)
When heat Q is supplied to a diatomic gas of rigid molecules, at constant volume its temperature increases by
$$\Delta $$T. the heat required to produce the same change in temperature, at a constant pressure is :
$${7 \over 5}Q$$
$${3 \over 2}Q$$
$${2 \over 3}Q$$
$${5 \over 3}Q$$
Explanation
Heat supplied at constant volume
Q = nCV$$\Delta $$T
and heat supplied at constant pressure
Q' = nCP$$\Delta $$T
$$Q' = {{{C_P}} \over {{C_V}}}Q = \left( {1 + {2 \over 5}} \right)Q = {7 \over 5}Q$$
Q = nCV$$\Delta $$T
and heat supplied at constant pressure
Q' = nCP$$\Delta $$T
$$Q' = {{{C_P}} \over {{C_V}}}Q = \left( {1 + {2 \over 5}} \right)Q = {7 \over 5}Q$$
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