JEE MAIN - Physics (2018 - 16th April Morning Slot - No. 5)

A ray of light is incident at an angle of 60^o on one face of a prism of angle 30^o. The emergent ray of light makes an angle of 30^o with incident ray. The angle made by the emergent ray with second face of prism will be :

0^o

90^o

45^o

30^o

Explanation

Given : $${i_1} = 60^\circ $$; $$A = 30^\circ $$

Then angle of deviation is given by

$$\delta = 1 - A = 60^\circ - 30^\circ = 30^\circ $$

JEE Main 2018 (Online) 16th April Morning Slot Physics - Geometrical Optics Question 186 English Explanation

We know that,

$${i_1} + {i_2} = A + \delta \Rightarrow 60^\circ + {i_2} = 30^\circ + 30^\circ \Rightarrow {i_2} = 0$$

It means emergent ray leaves face AC normally.

JEE MAIN - Physics (2018 - 16th April Morning Slot - No. 5)

Explanation

Comments (0)