JEE MAIN - Physics (2018 - 15th April Evening Slot - No. 5)
Truth table for the following digital circuit will be :
_15th_April_Evening_Slot_en_5_1.png)
_15th_April_Evening_Slot_en_5_2.png)
_15th_April_Evening_Slot_en_5_3.png)
_15th_April_Evening_Slot_en_5_4.png)
_15th_April_Evening_Slot_en_5_5.png)
Explanation
The given circuit is
_15th_April_Evening_Slot_en_5_6.png)
Therefore, truth table for given circuit is
| x | y | $$\overline x $$ | $$x\,.\,y$$ | $$\overline x \,.\,y$$ | $$(x\,.\,y)(\overline x y)$$ | $$z = \overline {(x\,.\,y)\,.\,(\overline x y)} $$ |
|---|---|---|---|---|---|---|
| 0 | 0 | 1 | 0 | 0 | 0 | 1 |
| 0 | 1 | 1 | 0 | 1 | 0 | 1 |
| 1 | 0 | 0 | 0 | 0 | 0 | 1 |
| 1 | 1 | 0 | 1 | 0 | 0 | 1 |
| x | y | z |
|---|---|---|
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 1 |
Comments (0)
