JEE MAIN - Physics (2017 - 9th April Morning Slot - No. 7)
Imagine that a reactor converts all given mass into energy and that it operates at a power level of 109 watt. The mass of the fuel consumed per hour in the reactor will be : (velocity of light, c is
3×108 m/s)
0.96 gm
0.8 gm
4 $$ \times $$ 10$$-$$2 gm
6.6 $$ \times $$ 10$$-$$5 gm
Explanation
The power can be calculated by the relation
$$P = {E \over {\Delta t}} = {{\Delta m{c^2}} \over {\Delta t}}$$ ...... (1)
Therefore, from Eq. (1), the mass of the fuel consumed per hour in the reactor is
$${{\Delta m} \over {\Delta t}} = {P \over {{c^2}}} = {{{{10}^9}} \over {{{(3 \times {{10}^8})}^2}}} = 4 \times {10^{ - 12}}$$ g
Comments (0)
