JEE MAIN - Physics (2017 - 8th April Morning Slot - No. 25)
The V-I characteristic of a diode is shown in the figure. The ratio of forward to reverse bias
resistance is :
_8th_April_Morning_Slot_en_25_1.png)
10
10$$-$$6
106
100
Explanation
Forward bias resistance
R1 = $${{\Delta V} \over {\Delta I}}$$ = $${{0.8 - 0.7} \over {\left( {20 - 10} \right) \times {{10}^{ - 3}}}}$$ = 10 $$\Omega $$
Reverse bias resistance,
R2 = $${{10} \over {1 \times {{10}^{ - 6}}}}$$ = 107 $$\Omega $$
$$\therefore\,\,\,$$ Ratio of resistance
= $${{{R_1}} \over {{R_2}}}$$ = $${{10} \over {{{10}^7}}}$$ = 10$$-$$6
R1 = $${{\Delta V} \over {\Delta I}}$$ = $${{0.8 - 0.7} \over {\left( {20 - 10} \right) \times {{10}^{ - 3}}}}$$ = 10 $$\Omega $$
Reverse bias resistance,
R2 = $${{10} \over {1 \times {{10}^{ - 6}}}}$$ = 107 $$\Omega $$
$$\therefore\,\,\,$$ Ratio of resistance
= $${{{R_1}} \over {{R_2}}}$$ = $${{10} \over {{{10}^7}}}$$ = 10$$-$$6
Comments (0)
