JEE MAIN - Physics (2017 (Offline) - No. 4)

In a coil of resistance 100 $$\Omega $$, a current is induced by changing the magnetic flux through it as shown in the figure. The magnitude of change in flux through the coil is:

JEE Main 2017 (Offline) Physics - Electromagnetic Induction Question 112 English
275 Wb
200 Wb
225 Wb
250 Wb

Explanation

According to Faraday's law of electromagnetic induction,

$$\varepsilon = {{d\phi } \over {dt}}$$

Also, $$\varepsilon $$ = iR

$$ \therefore $$ $${{d\phi } \over {dt}}$$ = iR

$$ \Rightarrow $$ $$\int {d\phi } = R\int {idt} $$

Magnitude of change in flux (d$$\phi $$) = R × area under current vs time graph

$$ \Rightarrow $$ d$$\phi $$ = $$100 \times {1 \over 2} \times {1 \over 2} \times 10$$ = 250 Wb

Comments (0)

Advertisement