JEE MAIN - Physics (2017 (Offline) - No. 17)
A copper ball of mass 100 gm is at a temperature T. It is dropped in a copper calorimeter of mass 100 gm,
filled with 170 gm of water at room temperature. Subsequently, the temperature of the system is found to
be 75oC. T is given by: (Given : room temperature = 30oC, specific heat of copper = 0.1 cal/gmoC)
825oC
800oC
885oC
1250oC
Explanation
According to principle of calorimetry,
Heat lost = Heat gain
100 × 0.1( – 75) = 100 × 0.1 × 45 + 170 × 1 × 45
10 – 750 = 450 + 7650
10 = 1200 + 7650 = 8850
T = 885°C
Heat lost = Heat gain
100 × 0.1( – 75) = 100 × 0.1 × 45 + 170 × 1 × 45
10 – 750 = 450 + 7650
10 = 1200 + 7650 = 8850
T = 885°C
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