JEE MAIN - Physics (2017 (Offline) - No. 13)
CP and Cv are specific heats at constant pressure and constant volume respectively. It is observed that
CP – Cv = a for hydrogen gas
CP – Cv = b for nitrogen gas
The correct relation between a and b is
CP – Cv = a for hydrogen gas
CP – Cv = b for nitrogen gas
The correct relation between a and b is
a = 28 b
a = 1/14 b
a = b
a = 14 b
Explanation
As we know, for 1 g mole of a gas,
Cp – Cv = R where Cp and Cv are molar specific heat capacities.
So, when n gram moles are given,
Cp – Cv = $${R \over n}$$
For hydrogen (n = 2), Cp – Cv = $${R \over 2}$$ = $$a$$
For nitrogen (n = 28), Cp – Cv = $${R \over 28}$$ = $$b$$
$$ \therefore $$ $${a \over b} = 14$$
$$ \Rightarrow $$ $$a$$ = 14 $$b$$
Cp – Cv = R where Cp and Cv are molar specific heat capacities.
So, when n gram moles are given,
Cp – Cv = $${R \over n}$$
For hydrogen (n = 2), Cp – Cv = $${R \over 2}$$ = $$a$$
For nitrogen (n = 28), Cp – Cv = $${R \over 28}$$ = $$b$$
$$ \therefore $$ $${a \over b} = 14$$
$$ \Rightarrow $$ $$a$$ = 14 $$b$$
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