JEE MAIN - Physics (2016 - 9th April Morning Slot - No. 23)
A series LR circuit is connected to a voltage source with
V(t) = V0 sin$$\Omega $$t. After very large time, current I(t) behaves as
(t0 >> $${L \over R}$$) :
V(t) = V0 sin$$\Omega $$t. After very large time, current I(t) behaves as
(t0 >> $${L \over R}$$) :
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Explanation
Current in LR circuit,
$${\rm I} = {{{V_0}} \over {\sqrt {{R^2} + {w^2}{L^2}} }}\sin \left( {\omega t - {\pi \over 2}} \right)$$
it will be a sinusoidal wave.
$${\rm I} = {{{V_0}} \over {\sqrt {{R^2} + {w^2}{L^2}} }}\sin \left( {\omega t - {\pi \over 2}} \right)$$
it will be a sinusoidal wave.
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