JEE MAIN - Physics (2016 - 10th April Morning Slot - No. 4)

Velocity-time graph for a body of mass 10 kg is shown in figure. Work-done on the body in first two seconds of the motion is :

JEE Main 2016 (Online) 10th April Morning Slot Physics - Work Power & Energy Question 103 English
12000 J
$$-$$ 12000 J
$$-$$ 4500 J
$$-$$ 9300 J

Explanation

JEE Main 2016 (Online) 10th April Morning Slot Physics - Work Power & Energy Question 103 English Explanation
Here u = 50 m/s , what t = 0

$$\alpha $$  =  $${{\Delta v} \over {\Delta t}}$$  =  $${{50 - 0} \over {0 - 10}}$$  =  $$-$$5 m/s2

Speed of the body at t = 2 s

v   =   u + at

=  50 + ($$-$$ 5) $$ \times $$ 2

=  40 m/s

From work energy theorem,

$$\Delta $$w  =  $${1 \over 2}m{v^2} - {1 \over 2}m{u^2}$$

=  $${1 \over 2}$$ m(v2 $$-$$u2)

= $${1 \over 2}$$ $$ \times $$ 10 $$ \times $$ (402 $$-$$ 502)

=  5 $$ \times $$ ($$-$$10)(90)

=  $$-$$ 4500 J

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