JEE MAIN - Physics (2013 (Offline) - No. 2)
A circular loop of radius $$0.3$$ $$cm$$ lies center of the small loop is on the axis of the bigger loop. The distance between their centers is $$15$$ $$cm.$$ If a current of $$2.0$$ $$A$$ flows through the smaller loop, than the flux linked with bigger loop is
$$9.1 \times {10^{ - 11}}\,$$ weber
$$6 \times {10^{ - 11}}\,$$ weber
$$3.3 \times {10^{ - 11}}\,$$ weber
$$6.6 \times {10^{ - 9}}\,$$ weber
Explanation
As we know, Magnetic flux, $$\phi = B.A$$
$${{{\mu _0}\left( 2 \right){{\left( {20 \times {{10}^{ - 2}}} \right)}^2}} \over {2\left[ {{{\left( {0.2} \right)}^2} + {{\left( {0.15} \right)}^2}} \right]}} \times \pi {\left( {0.3 \times {{10}^{ - 2}}} \right)^2}$$
On solving
$$ = 9.216 \times {10^{ - 11}} = 9.2 \times {10^{ - 11}}\,\,$$ weber
$${{{\mu _0}\left( 2 \right){{\left( {20 \times {{10}^{ - 2}}} \right)}^2}} \over {2\left[ {{{\left( {0.2} \right)}^2} + {{\left( {0.15} \right)}^2}} \right]}} \times \pi {\left( {0.3 \times {{10}^{ - 2}}} \right)^2}$$
On solving
$$ = 9.216 \times {10^{ - 11}} = 9.2 \times {10^{ - 11}}\,\,$$ weber
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