JEE MAIN - Physics (2011 - No. 7)
A boat is moving due east in a region where the earth's magnetic fields is $$5.0 \times {10^{ - 5}}$$ $$N{A^{ - 1}}\,{m^{ - 1}}$$ due north and horizontal. The best carries a vertical aerial $$2$$ $$m$$ long. If the speed of the boat is $$1.50\,m{s^{ - 1}},$$ the magnitude of the induced $$emf$$ in the wire of aerial is :
$$0.75$$ $$mV$$
$$0.50$$ $$mV$$
$$0.15$$ $$mV$$
$$1$$ $$mV$$
Explanation
Induced $$emf$$ $$ = v{B_H}l = 1.5 \times 5 \times {10^{ - 5}} \times 2$$
$$ = 15 \times {10^{ - 5}} = 0.15\,mV$$
$$ = 15 \times {10^{ - 5}} = 0.15\,mV$$
Comments (0)
