JEE MAIN - Physics (2007 - No. 31)
If $${C_p}$$ and $${C_v}$$ denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then
$${C_p} - {C_v} = 28R$$
$${C_p} - {C_v} = R/28$$
$${C_p} - {C_v} = R/14$$
$${C_p} - {C_v} = R$$
Explanation
According to Mayer's relationship $${C_p} - {C_v} = R$$
$$\therefore$$ $${{{C_p}} \over M} - {{{C_v}} \over M} = {R \over M}$$ $$\,\,\,\,\,\,$$ Here $$M=28.$$
$$\therefore$$ $${{{C_p}} \over M} - {{{C_v}} \over M} = {R \over M}$$ $$\,\,\,\,\,\,$$ Here $$M=28.$$
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