JEE MAIN - Physics (2007 - No. 1)
If $${M_O}$$ is the mass of an oxygen isotope $${}_8{O^{17}}$$ , $${M_p}$$ and $${M_N}$$ are the masses of a proton and neutron respectively, the nuclear binding energy of the isotope is
$$\left( {{M_O} - 17{M_N}} \right){C^2}$$
$$\left( {{M_O} - 8{M_P}} \right){C^2}$$
$$\left( {{M_O} - 8{M_P} - 9{M_N}} \right){C^2}$$
$${{M_O}{c^2}}$$
Explanation
Binding energy
$$ = \left[ {Z{M_p} + \left( {A - Z} \right){M_N} - M} \right]{c^2}$$
$$ = \left[ {8{M_p} + \left( {17 - 8} \right){M_N} - M} \right]{c^2}$$
$$ = \left[ {8{M_p} + 9{M_N} - M} \right]{c^2}$$
$$ = \left[ {8{M_p} + 9{M_N} - {M_O}} \right]{c^2}$$
$$ = \left[ {Z{M_p} + \left( {A - Z} \right){M_N} - M} \right]{c^2}$$
$$ = \left[ {8{M_p} + \left( {17 - 8} \right){M_N} - M} \right]{c^2}$$
$$ = \left[ {8{M_p} + 9{M_N} - M} \right]{c^2}$$
$$ = \left[ {8{M_p} + 9{M_N} - {M_O}} \right]{c^2}$$
Comments (0)
