JEE MAIN - Physics (2005 - No. 23)
One conducting $$U$$ tube can slide inside another as shown in figure, maintaining electrical contacts between the tubes. The magnetic field $$B$$ is perpendicular to the plane of the figure. If each tube moves towards the other at a constant speed $$v,$$ then the $$emf$$ induced in the circuit in terms of $$B,l$$ and $$v$$ where $$l$$ is the width of each tube, will be


$$-Blv$$
$$blv$$
$$2$$ $$Blv$$
zero
Explanation
Relative velocity $$ = v + v = 2v$$
$$\therefore$$ $$emf.$$ $$ = B.l\left( {2v} \right)$$
$$\therefore$$ $$emf.$$ $$ = B.l\left( {2v} \right)$$
Comments (0)
