JEE MAIN - Physics (2005 - No. 2)
A nuclear transformation is denoted by $$X\left( {n,\alpha } \right)\matrix{
7 \cr
3 \cr
} Li.$$ Which of the following is the nucleus of element $$X$$ ?
$${}_5^{10}B$$
$${}^{12}{C_6}$$
$${}_4^{11}Be$$
$${}_5^9B$$
Explanation
$${}_z{X^A} + {}_0{n^1} \to {}_3L{i^7} + {}_2H{e^4}$$
On comparison,
$$A = 7 + 4 - 1 = 10,\,\,\,z = 3 + 2 - 0 = 5$$
It is boron $${}_5{B^{10}}$$
On comparison,
$$A = 7 + 4 - 1 = 10,\,\,\,z = 3 + 2 - 0 = 5$$
It is boron $${}_5{B^{10}}$$
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