JEE MAIN - Physics (2004 - No. 66)
Two masses $${m_1} = 5kg$$ and $${m_2} = 4.8kg$$ tied to a string are hanging over a light frictionless pulley. What is the acceleration of the masses when left free to move? $$\left( {g = 9.8m/{s^2}} \right)$$
$$5\,\,m/{s^2}$$
$$9.8\,\,m/{s^2}$$
$$0.2\,\,m/{s^2}$$
$$4.8\,\,m/{s^2}$$
Explanation
For m1 mass :
m1g - T = m1a .........(1)
For m2 mass :
T - m2g = m2a ....... (2)
By solving (1) and (2) we get,
Acceleration a = $$\left( {{{{m_1} - {m_2}} \over {{m_1} + {m_2}}}} \right)g$$
$$ = {{\left( {5 - 4.8} \right) \times 9.8} \over {\left( {5 + 4.8} \right)}}m/{s^2}$$ = 0.2 m/s2
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