JEE MAIN - Physics (2004 - No. 64)
The displacement $$y$$ of a particle in a medium can be expressed as, $$y = {10^{ - 6}}\,\sin $$ $$\left( {100t + 20x + {\pi \over 4}} \right)$$ $$m$$ where $$t$$ is in second and $$x$$ in meter. The speed of the wave is
$$20\,\,m/s$$
$$5\,m/s$$
$$2000\,m/s$$
$$5\,\pi \,m/s$$
Explanation
From equation given,
$$\omega = 100$$ and $$k = 20,$$ $$v = {\omega \over k} = {{100} \over {20}} = 5m/s$$
$$\omega = 100$$ and $$k = 20,$$ $$v = {\omega \over k} = {{100} \over {20}} = 5m/s$$
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