JEE MAIN - Physics (2004 - No. 54)
If two soap bubbles of different radii are connected by a tube
air flows from the smaller bubble to the bigger
air flows from bigger bubble to the smaller bubble till the sizes are interchanged
air flows from the bigger bubble to the smaller bubble till the sizes become equal
there is no flow of air.
Explanation
Pressure inside the bubble, P $$ = {p_0} + {{4T} \over R}$$
So $$P \propto {1 \over R}$$ where R is the radius of the bubble. It means pressure inside a smaller bubble is greater than the inside of a bigger bubble.
So when two bubbles are connected by a tube, air will flow from smaller bubble to bigger bubble and the size of bigger bubble will increase.
So $$P \propto {1 \over R}$$ where R is the radius of the bubble. It means pressure inside a smaller bubble is greater than the inside of a bigger bubble.
So when two bubbles are connected by a tube, air will flow from smaller bubble to bigger bubble and the size of bigger bubble will increase.
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