JEE MAIN - Physics (2003 - No. 60)
A block of mass $$M$$ is pulled along a horizontal frictionless surface by a rope of mass $$m.$$ If a force $$P$$ is applied at the free end of the rope, the force exerted by the rope on the block is
$${{Pm} \over {M + m}}$$
$${{Pm} \over {M - m}}$$
$$P$$
$${{PM} \over {M + m}}$$
Explanation
Taking the rope and the block as a system
Acceleration of block($$a$$) = $${{Force\,applied} \over {total\,mass}}$$
$$\therefore$$ $$a = {P \over {m + M}}$$
Force on block(T) = Mass of block $$ \times $$ $$a$$
$$T=Ma$$
$$\therefore$$ $$T = {{MP} \over {m + M}}$$
Acceleration of block($$a$$) = $${{Force\,applied} \over {total\,mass}}$$
$$\therefore$$ $$a = {P \over {m + M}}$$
Force on block(T) = Mass of block $$ \times $$ $$a$$
$$T=Ma$$
$$\therefore$$ $$T = {{MP} \over {m + M}}$$
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