JEE MAIN - Physics (2003 - No. 46)
The displacement $$y$$ of a wave travelling in the $$x$$-direction is given by
$$$y = {10^{ - 4}}\,\sin \left( {600t - 2x + {\pi \over 3}} \right)\,\,metres$$$
where $$x$$ is expressed in metres and $$t$$ in seconds. The speed of the wave - motion, in $$m{s^{ - 1}}$$, is
where $$x$$ is expressed in metres and $$t$$ in seconds. The speed of the wave - motion, in $$m{s^{ - 1}}$$, is
$$300$$
$$600$$
$$1200$$
$$200$$
Explanation
$$y = {10^{ - 4}}\sin \left( {600t - 2x + {\pi \over 3}} \right)$$
But $$y = A\sin \left( {\omega t - kx + \phi } \right)$$
On comparing we get $$\omega = 600;\,k = 2$$
$$v = {\omega \over k} = {{600} \over 2} = 300\,m{s^{ - 1}}$$
But $$y = A\sin \left( {\omega t - kx + \phi } \right)$$
On comparing we get $$\omega = 600;\,k = 2$$
$$v = {\omega \over k} = {{600} \over 2} = 300\,m{s^{ - 1}}$$
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