JEE MAIN - Physics (2003 - No. 34)
Three forces start acting simultaneously on a particle moving with velocity, $$\overrightarrow v \,\,.$$ These forces are represented in magnitude and direction by the three sides of a triangle $$ABC$$. The particle will now move with velocity
less than $$\overrightarrow v \,$$
greater than $$\overrightarrow v \,$$
$$\left| v \right|$$ in the direction of the largest force $$BC$$
$$\overrightarrow v \,\,,$$ remaining unchanged
Explanation
As shown in the figure, the three forces are represented by the sides of a triangle taken in the same order. So the particle will be in equilibrium under the three forces.
Therefore the resultant force is zero.
We know, $${\overrightarrow F_{net}} = m\overrightarrow a .$$
$$\therefore$$ 0 = $$ m\overrightarrow a .$$
$$ \Rightarrow \overrightarrow a = 0$$
Therefore acceleration will be zero.
Hence the particle velocity remains unchanged.
Therefore the resultant force is zero.
We know, $${\overrightarrow F_{net}} = m\overrightarrow a .$$
$$\therefore$$ 0 = $$ m\overrightarrow a .$$
$$ \Rightarrow \overrightarrow a = 0$$
Therefore acceleration will be zero.
Hence the particle velocity remains unchanged.
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