JEE MAIN - Physics (2002 - No. 61)
Three identical blocks of masses $$m=2$$ $$kg$$ are drawn by a force $$F=10.2$$ $$N$$ with an acceleration of $$0.6$$ $$m{s^{ - 2}}$$ on a frictionless surface, then what is the tension (in $$N$$) in the string between the blocks $$B$$ and $$C$$?
$$9.2$$
$$3.4$$
$$4$$
$$7.8$$
Explanation
Assume tension between block A and B is T1 and block B and C is T2. Acceleration a = 0.6 m/s2.
For block A :
F - T1 = ma
For block B :
T1 - T2 = ma
By adding both those equation we get,
F - T2 = 2ma
T2 = F - 2ma
T2 = 10.2 - 2$$ \times $$2$$ \times $$0.6 = 10.2 - 2.4 = 7.8 N
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