JEE MAIN - Physics (2002 - No. 5)
If $${\theta _1},$$ is the inversion temperature, $${\theta _n}$$ is the neutral temperature, $${\theta _c}$$ is the temperature of the cold junction, then
$${\theta _i} + {\theta _c} = {\theta _n}$$
$${\theta _i} - {\theta _c} = 2{\theta _n}$$
$${{{\theta _i} + {\theta _C}} \over 2} = {\theta _n}$$
$${\theta _c} - {\theta _i} = 2{\theta _n}$$
Explanation
$${\theta _n} = {{{\theta _i} + {\theta _c}} \over 2}.$$
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