JEE MAIN - Physics (2002 - No. 30)
One end of a mass-less rope, which passes over a mass-less and friction-less pulley $$P$$ is tied to a hook $$C$$ while the other end is free. Maximum tension that the rope can bear is $$360$$ $$N.$$ With what value of maximum safe acceleration (in $$m{s^{ - 2}}$$) can a man of $$60$$ $$kg$$ climb on the rope?
$$16$$
$$6$$
$$4$$
$$8$$
Explanation
Assuming acceleration $$a$$ of the man is downwards.
So the equation will be
$$mg - T = ma$$
$$\therefore$$ $$a = g - {T \over m} = 10 - {{360} \over {60}} = 4$$ $$ m/{s^2}$$
So the maximum acceleration of man is 4 m/s2 downwards.
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