JEE MAIN - Physics (2002 - No. 28)
The escape velocity of a body depends upon mass as
$${m^0}$$
$${m^1}$$
$${m^2}$$
$${m^3}$$
Explanation
Escape velocity,
$${v_e} = \sqrt {2gR} = \sqrt {{{2GM} \over R}} \Rightarrow {V_e}\, \propto \,{m^0}$$
$${v_e} = \sqrt {2gR} = \sqrt {{{2GM} \over R}} \Rightarrow {V_e}\, \propto \,{m^0}$$
Where $$M,R$$ are the mass and radius of the planet respectively. In this expression the mass of the body $$(m)$$ is not present. The escape velocity is independent of the mass m or it depends on m0.
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