JEE MAIN - Physics (2002 - No. 10)
If an electron and a proton having same momentum enter perpendicular to a magnetic field, then
curved path of electron and proton will be same (ignoring the sense of revolution)
they will move undeflected
curved path of electron is more curved than that of the proton
path of proton is more curved.
Explanation
KEY CONCEPT : When a charged particle enters perpendicular to a magnetic field,
then it moves in a circular path of radius.
$$r = {p \over {qB}}$$
where $$q=$$ Charge of the particle
$$p=$$ Momentum of the particle
$$B=$$ Magnetic field
Here $$p,q$$ and $$B$$ are constant for electron and proton, therefore the radius will be
same.
then it moves in a circular path of radius.
$$r = {p \over {qB}}$$
where $$q=$$ Charge of the particle
$$p=$$ Momentum of the particle
$$B=$$ Magnetic field
Here $$p,q$$ and $$B$$ are constant for electron and proton, therefore the radius will be
same.
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