JEE MAIN - Physics Hindi (2025 - 8th April Evening Shift - No. 8)

The amplitude and phase of a wave that is formed by the superposition of two harmonic travelling waves, $\mathrm{y}_1(x, \mathrm{t})=4 \sin (\mathrm{kx}-\omega \mathrm{t})$ and $\mathrm{y}_2(x, \mathrm{t})=2 \sin \left(\mathrm{k} x-\omega \mathrm{t}+\frac{2 \pi}{3}\right)$, are: (Take the angular frequency of initial waves same as $\omega$ )
$[\sqrt{3}, \pi / 6]$
$[2 \sqrt{3}, \pi / 6]$
$[6,2 \pi / 3]$
$[6, \pi / 3]$

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