JEE MAIN - Physics Hindi (2024 - 4th April Evening Shift - No. 5)
A sample of gas at temperature $$T$$ is adiabatically expanded to double its volume. Adiabatic constant for the gas is $$\gamma=3 / 2$$. The work done by the gas in the process is:
$$(\mu=1 \text { mole})$$
$$R T[2 \sqrt{2}-1]$$
$$R T[2-\sqrt{2}]$$
$$R T[1-2 \sqrt{2}]$$
$$R T[\sqrt{2}-2]$$
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