JEE MAIN - Physics Hindi (2023 - 8th April Morning Shift - No. 5)

$$\frac{1}{\mu_0 \epsilon_0}$$ की विमा होगी:
$$\mathrm{T}^2 / \mathrm{L}^2$$
$$\mathrm{T} / \mathrm{L}$$
$$\mathrm{L}^2 / \mathrm{T}^2$$
$$\mathrm{L} / \mathrm{T}$$

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