JEE MAIN - Physics Hindi (2021 - 26th August Evening Shift - No. 5)
वेक्टर $$\left( {\overrightarrow A } \right)$$ और $$\left( {\overrightarrow A - \overrightarrow B } \right)$$ के बीच का कोण है :
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$${\tan ^{ - 1}}\left( {{{ - {B \over 2}} \over {A - B{{\sqrt 3 } \over 2}}}} \right)$$
$${\tan ^{ - 1}}\left( {{A \over {0.7B}}} \right)$$
$${\tan ^{ - 1}}\left( {{{\sqrt 3 B} \over {2A - B}}} \right)$$
$${\tan ^{ - 1}}\left( {{{B\cos \theta } \over {A - B\sin \theta }}} \right)$$
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