JEE MAIN - Mathematics (2025 - 7th April Morning Shift - No. 9)

The remainder when $\left((64)^{(64)}\right)^{(64)}$ is divided by 7 is equal to
4
6
3
1

Explanation

$$\begin{aligned} &\begin{aligned} & 64^{64} \Rightarrow(63+1)^{64}=63 \lambda+1 \\ & 64^{664^{64}} \Rightarrow(63+1)^{64^{64}} \\ & 63 \lambda_1+1 \end{aligned}\\ &\text { Required remainder when divided } 7 \text { is } 1 \text {. } \end{aligned}$$

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