$$\begin{aligned} &\begin{aligned} & x R y \Leftrightarrow 2 x-y \in\{0,1\} \\ & \Rightarrow \quad y=2 x \text { or } y=2 x-1 \\ & A=\{-3,-2,-1,0,1,2,3\} \\ & \mathrm{R}=\{(-1,-2),(0,0),(1,2),(-1,-3),(0,-1),(1,1), \\ & (2,3)\} \\ & \Rightarrow \quad I=7 \end{aligned}\\ &\text { For } R \text { to be reflexive }(0,0),(1,1) \in R \end{aligned}$$

But other $(a, a)$ such that $2 a-a \in\{0,1\}$

$$\Rightarrow \quad a \in\{0,1\}$$

5 other pairs needs to be added $\Rightarrow m=5$

$x R y \Rightarrow y R x$ to be symmetric

$(-1,-2) \Rightarrow(-2,-1)$

$(1,2) \Rightarrow(2,1)$

$(-1,-3) \Rightarrow(-3,-1)$

$(0,-1) \Rightarrow(-1,0)$

$(2,3) \Rightarrow(3,2) \Rightarrow 5$ needs to be added, $n=5$

$\Rightarrow \quad l+m+n=17$