JEE MAIN - Mathematics (2025 - 3rd April Morning Shift - No. 4)
$$
\text { The number of solutions of the equation } 2 x+3 \tan x=\pi, x \in[-2 \pi, 2 \pi]-\left\{ \pm \frac{\pi}{2}, \pm \frac{3 \pi}{2}\right\} \text { is: }
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4
5
3
6
Explanation
$$\begin{aligned} & 2 x+3 \tan x=\pi \\ & \Rightarrow \quad \tan x=\frac{\pi-2 x}{3}, x \in[-2 \pi, 2 \pi]-\left\{ \pm \frac{\pi}{2}, \pm \frac{3 \pi}{2}\right\} \end{aligned}$$
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5 solutions
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