JEE MAIN - Mathematics (2025 - 23rd January Evening Shift - No. 14)
Let $\mathrm{A}=\{(x, y) \in \mathbf{R} \times \mathbf{R}:|x+y| \geqslant 3\}$ and $\mathrm{B}=\{(x, y) \in \mathbf{R} \times \mathbf{R}:|x|+|y| \leq 3\}$.
If $\mathrm{C}=\{(x, y) \in \mathrm{A} \cap \mathrm{B}: x=0$ or $y=0\}$, then $\sum_{(x, y) \in \mathrm{C}}|x+y|$ is :
18
24
15
12
Explanation
_23rd_January_Evening_Shift_en_14_1.png)
$$\begin{aligned} & \mathrm{C}=\{(3,0),(-3,0),(0,3),(0,-3)\} \\ & \Sigma|\mathrm{x}+\mathrm{y}|=12 \end{aligned}$$
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