To find the value of $$\frac{3 \cos 36^{\circ}+5 \sin 18^{\circ}}{5 \cos 36^{\circ}-3 \sin 18^{\circ}}$$ in the form $$\frac{a \sqrt{5}-b}{c}$$, we need to simplify the given expression. Let's start by using some fundamental trigonometric identities.

We know that:

$$\cos 36^{\circ} = \frac{\sqrt{5} + 1}{4}$$

$$\sin 18^{\circ} = \frac{\sqrt{5} - 1}{4}$$

First, substitute these values into the expression:

$$\frac{3 \cdot \frac{\sqrt{5} + 1}{4} + 5 \cdot \frac{\sqrt{5} - 1}{4}}{5 \cdot \frac{\sqrt{5} + 1}{4} - 3 \cdot \frac{\sqrt{5} - 1}{4}}$$

Simplify the numerator and the denominator:

Numerator: $$3 \cdot \frac{\sqrt{5} + 1}{4} + 5 \cdot \frac{\sqrt{5} - 1}{4} = \frac{3(\sqrt{5} + 1) + 5(\sqrt{5} - 1)}{4} = \frac{3\sqrt{5} + 3 + 5\sqrt{5} - 5}{4} = \frac{8\sqrt{5} - 2}{4} = 2 \sqrt{5} - \frac{1}{2}$$

Denominator: $$5 \cdot \frac{\sqrt{5} + 1}{4} - 3 \cdot \frac{\sqrt{5} - 1}{4} = \frac{5(\sqrt{5} + 1) - 3(\sqrt{5} - 1)}{4} = \frac{5\sqrt{5} + 5 - 3\sqrt{5} + 3}{4} = \frac{2\sqrt{5} + 8}{4} = \frac{\sqrt{5}+4}{2}$$

Now combine the simplified numerator and denominator:

$$\frac{2 \sqrt{5} - \frac{1}{2}}{\frac{\sqrt{5}+4}{2}} = \frac{(2 \sqrt{5} - \frac{1}{2}) \cdot 2}{\sqrt{5}+4} = \frac{4 \sqrt{5} - 1}{\sqrt{5}+4}$$

Rationalizing the denominator by multiplying both the numerator and the denominator by the conjugate of the denominator:

$$\frac{(4 \sqrt{5} - 1)(\sqrt{5}-4)}{(\sqrt{5}+4)(\sqrt{5}-4)}$$

The denominator simplifies to:

$$ \sqrt{5}^2 - 4^2 = 5 - 16 = -11$$

The numerator simplifies to:

$$ (4 \sqrt{5} - 1)(\sqrt{5}-4) = (4 \sqrt{5} \cdot \sqrt{5} - 4 \cdot 4 \sqrt{5} - 1 \cdot \sqrt{5} + 1 \cdot 4) = (20 - 16 \sqrt{5} - \sqrt{5} + 4) = 24 - 17 \sqrt{5}$$

Combining them, we get:

$$\frac{24 - 17\sqrt{5}}{-11} = \frac{17\sqrt{5}-24}{11}$$

Thus, $$a = 17, b = 24, c = 11$$.

Therefore, $$a + b + c = 17 + 24 + 11 = 52$$.

So the correct option is:

Option B: 52