JEE MAIN - Mathematics (2024 - 6th April Evening Shift - No. 28)
If the system of equations
$$\begin{aligned} & 2 x+7 y+\lambda z=3 \\ & 3 x+2 y+5 z=4 \\ & x+\mu y+32 z=-1 \end{aligned}$$
has infinitely many solutions, then $$(\lambda-\mu)$$ is equal to ______ :
Explanation
To determine if the system of equations:
$$\begin{aligned} 2x + 7y + \lambda z = 3 \\ 3x + 2y + 5z = 4 \\ x + \mu y + 32z = -1 \end{aligned}$$
has infinitely many solutions, we must use Cramer's rule.
The determinants are calculated as follows:
$$\begin{aligned} \Delta &= -2\lambda + 3\lambda\mu - 10\mu - 509 \\ \Delta_1 &= 2\lambda + 3\lambda\mu - 15\mu - 739 \\ \Delta_2 &= -7\lambda - 7 \\ \Delta_3 &= \mu + 39 \end{aligned}$$
To have infinitely many solutions, the determinants must satisfy:
$$\begin{aligned} \Delta = \Delta_1 = \Delta_2 = \Delta_3 = 0 \end{aligned}$$
Solving these equations, we find:
$$\lambda = -1, \mu = -39$$
Thus, the value of $ \lambda - \mu $ is:
$$ \lambda - \mu = 38 $$
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