JEE MAIN - Mathematics (2024 - 5th April Morning Shift - No. 7)
Let a circle C of radius 1 and closer to the origin be such that the lines passing through the point $$(3,2)$$ and parallel to the coordinate axes touch it. Then the shortest distance of the circle C from the point $$(5,5)$$ is :
4$$\sqrt2$$
4
5
2$$\sqrt2$$
Explanation
_5th_April_Morning_Shift_en_7_1.png)
Shortest distance of circle $$C$$ form $$(5,5)$$
$$\begin{aligned} & =\sqrt{9+16}-1 \\ & =5-1=4 \end{aligned}$$
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