JEE MAIN - Mathematics (2024 - 5th April Morning Shift - No. 24)

The number of ways of getting a sum 16 on throwing a dice four times is ________.
Answer
125

Explanation

Number of ways $$=$$ coefficient of $$x^{16}$$ in $$\left(x+x^2+\ldots+\right.$$ $$\left.x^6\right)^4$$

$$=$$ coefficient of $$x^{16}$$ in $$\left(1-x^6\right)^4(1-x)^{-4}$$

$$=$$ coefficient of $$x^{16}$$ in $$\left(1-4 x^6+6 x^{12} \ldots\right)(1-x)^{-4}$$

$$={ }^{15} C_3-4 \cdot{ }^9 C_3+6=125$$

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