JEE MAIN - Mathematics (2024 - 30th January Morning Shift - No. 12)
Let M denote the median of the following frequency distribution
| Class | 0 - 4 | 4 - 8 | 8 - 12 | 12 - 16 | 16 - 20 |
|---|---|---|---|---|---|
| Frequency | 3 | 9 | 10 | 8 | 6 |
Then 20M is equal to :
104
52
208
416
Explanation
| Class | Frequency | Cumulative frequency |
|---|---|---|
| 0-4 | 3 | 3 |
| 4-8 | 9 | 12 |
| 8-12 | 10 | 22 |
| 12-16 | 8 | 30 |
| 16-20 | 6 | 36 |
$$\begin{aligned} & \mathrm{M}=1+\left(\frac{\frac{\mathrm{N}}{2}-\mathrm{C}}{\mathrm{f}}\right) \mathrm{h} \\ & \mathrm{M}=8+\frac{18-12}{10} \times 4 \\ & \mathrm{M}=10.4 \\ & 20 \mathrm{M}=208 \end{aligned}$$
Comments (0)
