JEE MAIN - Mathematics (2022 - 29th July Morning Shift - No. 2)
If $$z=2+3 i$$, then $$z^{5}+(\bar{z})^{5}$$ is equal to :
244
224
245
265
Explanation
$$z = (2 + 3i)$$
$$ \Rightarrow {z^5} = (2 + 3i){\left( {{{(2 + 3i)}^2}} \right)^2}$$
$$ = (2 + 3i){( - 5 + 12i)^2}$$
$$ = (2 + 3i)( - 119 - 120i)$$
$$ = - 238 - 240i - 357i + 360$$
$$ = 122 - 597i$$
$${\overline z ^5} = 122 + 597i$$
$${z^5} + {\overline z ^5} = 244$$
Comments (0)
