JEE MAIN - Mathematics (2022 - 27th June Morning Shift - No. 5)
The number of distinct real roots of x4 $$-$$ 4x + 1 = 0 is :
4
2
1
0
Explanation
$$f(x) = {x^4} - 4x + 1 = 0$$
$$f'(x) = 4{x^3} - 4$$
$$ = 4(x - 1)({x^2} + 1 + x)$$
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$$\Rightarrow$$ Two solution
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