JEE MAIN - Mathematics (2022 - 26th July Evening Shift - No. 16)
Numbers are to be formed between 1000 and 3000 , which are divisible by 4 , using the digits $$1,2,3,4,5$$ and 6 without repetition of digits. Then the total number of such numbers is ____________.
Answer
30
Explanation
Here 1st digit is 1 or 2 only
Case-I
If first digit is 1
Then last two digits can be 24, 32, 36, 52, 56, 64
_26th_July_Evening_Shift_en_16_1.png)
Case – II
If first digit is 2 then last two digit can be 16, 36, 56, 64
_26th_July_Evening_Shift_en_16_2.png)
Total ways = 12 + 18 = 30 ways
Case-I
If first digit is 1
Then last two digits can be 24, 32, 36, 52, 56, 64
Case – II
If first digit is 2 then last two digit can be 16, 36, 56, 64
Total ways = 12 + 18 = 30 ways
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