JEE MAIN - Mathematics (2022 - 24th June Evening Shift - No. 21)
The area (in sq. units) of the region enclosed between the parabola y2 = 2x and the line x + y = 4 is __________.
Answer
18
Explanation
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The required area $$ = \int_{ - 4}^2 {\left( {4 - y - {{{y^2}} \over 2}} \right)dy} $$
$$ = \left[ {4y - {{{y^2}} \over 2} - {{{y^3}} \over 6}} \right]_{ - 4}^2$$
$$ = 18$$ square units
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