JEE MAIN - Mathematics (2021 - 26th February Morning Shift - No. 9)
In the circle given below, let OA = 1 unit, OB = 13 unit and PQ $$ \bot $$ OB. Then, the area of the triangle PQB (in square units) is :
_26th_February_Morning_Shift_en_9_1.png)
24$$\sqrt 2 $$
24$$\sqrt 3 $$
26$$\sqrt 2 $$
26$$\sqrt 3 $$
Explanation
_26th_February_Morning_Shift_en_9_2.png)
Let PA = AQ = $$\lambda$$
OA . AB = AP . AQ
$$ \Rightarrow $$ 1.12 = $$\lambda$$ . $$\lambda$$
$$ \Rightarrow $$ $$\lambda$$ = 2$$\sqrt 3 $$
Area $$\Delta$$PQB = $${1 \over 2}$$ $$\times$$ 2$$\lambda$$ $$\times$$ AB
$$\Delta$$ = $${1 \over 2}$$ . 4$$\sqrt 3 $$ $$\times$$ 12
= 24$$\sqrt 3 $$
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