JEE MAIN - Mathematics (2021 - 26th August Morning Shift - No. 6)

Out of all the patients in a hospital 89% are found to be suffering from heart ailment and 98% are suffering from lungs infection. If K% of them are suffering from both ailments, then K can not belong to the set :
{80, 83, 86, 89}
{84, 86, 88, 90}
{79, 81, 83, 85}
{84, 87, 90, 93}

Explanation

This solution begins by applying the principle of inclusion and exclusion, which in the context of this problem, is represented by the formula :

n(A ∪ B) ≥ n(A) + n(B) - n(A ∩ B)

Here, n(A ∪ B) represents the total number of patients in the hospital, which is 100%. n(A) represents the proportion of patients with a heart ailment (89%), and n(B) represents the proportion of patients with a lung infection (98%).

By rearranging this formula, the solution establishes an inequality for n(A ∩ B), the proportion of patients suffering from both ailments :

100% ≥ 89% + 98% - n(A ∩ B)

Therefore,

n(A ∩ B) ≥ 87%

Next, the solution notes that n(A ∩ B) cannot be greater than the smaller of n(A) and n(B), since it cannot be larger than the smallest group. Thus, we have another inequality :

n(A ∩ B) ≤ 89%

Combining these two inequalities gives :

87% ≤ n(A ∩ B) ≤ 89%

Hence, the proportion of patients suffering from both ailments must be a value between 87% and 89% inclusive. So, the set of values {79,81,83,85} which are all less than 87% are values that n(A ∩ B) cannot belong to. Therefore, option C is the correct answer.

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