JEE MAIN - Mathematics (2021 - 26th August Morning Shift - No. 6)
Explanation
This solution begins by applying the principle of inclusion and exclusion, which in the context of this problem, is represented by the formula :
n(A ∪ B) ≥ n(A) + n(B) - n(A ∩ B)
Here, n(A ∪ B) represents the total number of patients in the hospital, which is 100%. n(A) represents the proportion of patients with a heart ailment (89%), and n(B) represents the proportion of patients with a lung infection (98%).
By rearranging this formula, the solution establishes an inequality for n(A ∩ B), the proportion of patients suffering from both ailments :
100% ≥ 89% + 98% - n(A ∩ B)
Therefore,
n(A ∩ B) ≥ 87%
Next, the solution notes that n(A ∩ B) cannot be greater than the smaller of n(A) and n(B), since it cannot be larger than the smallest group. Thus, we have another inequality :
n(A ∩ B) ≤ 89%
Combining these two inequalities gives :
87% ≤ n(A ∩ B) ≤ 89%
Hence, the proportion of patients suffering from both ailments must be a value between 87% and 89% inclusive. So, the set of values {79,81,83,85} which are all less than 87% are values that n(A ∩ B) cannot belong to. Therefore, option C is the correct answer.
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