JEE MAIN - Mathematics (2021 - 24th February Evening Shift - No. 18)
The students S1, S2, ....., S10 are to be divided into 3 groups A, B and C such that each group has at least one student and the group C has at most 3 students. Then the total number of possibilities of forming such groups is ___________.
Answer
31650
Explanation
If group C has one student then number of
groups
= 10C1 [29 – 2] = 5100
If group C has two students then number of groups
= 10C2 [28 – 2] = 11430
If group C has three students then number of groups
= 10C3 × [27 – 2] = 15120
So total groups = 31650
= 10C1 [29 – 2] = 5100
If group C has two students then number of groups
= 10C2 [28 – 2] = 11430
If group C has three students then number of groups
= 10C3 × [27 – 2] = 15120
So total groups = 31650
Comments (0)
