JEE MAIN - Mathematics (2021 - 18th March Morning Shift - No. 9)
For the four circles M, N, O and P, following four equations are given :
Circle M : x2 + y2 = 1
Circle N : x2 + y2 $$-$$ 2x = 0
Circle O : x2 + y2 $$-$$ 2x $$-$$ 2y + 1 = 0
Circle P : x2 + y2 $$-$$ 2y = 0
If the centre of circle M is joined with centre of the circle N, further center of circle N is joined with centre of the circle O, centre of circle O is joined with the centre of circle P and lastly, centre of circle P is joined with centre of circle M, then these lines form the sides of a :
Circle M : x2 + y2 = 1
Circle N : x2 + y2 $$-$$ 2x = 0
Circle O : x2 + y2 $$-$$ 2x $$-$$ 2y + 1 = 0
Circle P : x2 + y2 $$-$$ 2y = 0
If the centre of circle M is joined with centre of the circle N, further center of circle N is joined with centre of the circle O, centre of circle O is joined with the centre of circle P and lastly, centre of circle P is joined with centre of circle M, then these lines form the sides of a :
Rhombus
Square
Rectangle
Parallelogram
Explanation
$${C_M} = (0,0)$$
$${C_N} = (1,0)$$
$${C_O} = (1,1)$$
$${C_P} = (0,1)$$
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$${C_N} = (1,0)$$
$${C_O} = (1,1)$$
$${C_P} = (0,1)$$
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